3.703 \(\int \frac{x^5}{\sqrt [3]{a+b x^2}} \, dx\)

Optimal. Leaf size=59 \[ \frac{3 a^2 \left (a+b x^2\right )^{2/3}}{4 b^3}+\frac{3 \left (a+b x^2\right )^{8/3}}{16 b^3}-\frac{3 a \left (a+b x^2\right )^{5/3}}{5 b^3} \]

[Out]

(3*a^2*(a + b*x^2)^(2/3))/(4*b^3) - (3*a*(a + b*x^2)^(5/3))/(5*b^3) + (3*(a + b*x^2)^(8/3))/(16*b^3)

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Rubi [A]  time = 0.0343872, antiderivative size = 59, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 15, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.133, Rules used = {266, 43} \[ \frac{3 a^2 \left (a+b x^2\right )^{2/3}}{4 b^3}+\frac{3 \left (a+b x^2\right )^{8/3}}{16 b^3}-\frac{3 a \left (a+b x^2\right )^{5/3}}{5 b^3} \]

Antiderivative was successfully verified.

[In]

Int[x^5/(a + b*x^2)^(1/3),x]

[Out]

(3*a^2*(a + b*x^2)^(2/3))/(4*b^3) - (3*a*(a + b*x^2)^(5/3))/(5*b^3) + (3*(a + b*x^2)^(8/3))/(16*b^3)

Rule 266

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a
+ b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rubi steps

\begin{align*} \int \frac{x^5}{\sqrt [3]{a+b x^2}} \, dx &=\frac{1}{2} \operatorname{Subst}\left (\int \frac{x^2}{\sqrt [3]{a+b x}} \, dx,x,x^2\right )\\ &=\frac{1}{2} \operatorname{Subst}\left (\int \left (\frac{a^2}{b^2 \sqrt [3]{a+b x}}-\frac{2 a (a+b x)^{2/3}}{b^2}+\frac{(a+b x)^{5/3}}{b^2}\right ) \, dx,x,x^2\right )\\ &=\frac{3 a^2 \left (a+b x^2\right )^{2/3}}{4 b^3}-\frac{3 a \left (a+b x^2\right )^{5/3}}{5 b^3}+\frac{3 \left (a+b x^2\right )^{8/3}}{16 b^3}\\ \end{align*}

Mathematica [A]  time = 0.0222005, size = 39, normalized size = 0.66 \[ \frac{3 \left (a+b x^2\right )^{2/3} \left (9 a^2-6 a b x^2+5 b^2 x^4\right )}{80 b^3} \]

Antiderivative was successfully verified.

[In]

Integrate[x^5/(a + b*x^2)^(1/3),x]

[Out]

(3*(a + b*x^2)^(2/3)*(9*a^2 - 6*a*b*x^2 + 5*b^2*x^4))/(80*b^3)

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Maple [A]  time = 0.005, size = 36, normalized size = 0.6 \begin{align*}{\frac{15\,{b}^{2}{x}^{4}-18\,ab{x}^{2}+27\,{a}^{2}}{80\,{b}^{3}} \left ( b{x}^{2}+a \right ) ^{{\frac{2}{3}}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^5/(b*x^2+a)^(1/3),x)

[Out]

3/80*(b*x^2+a)^(2/3)*(5*b^2*x^4-6*a*b*x^2+9*a^2)/b^3

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Maxima [A]  time = 1.66832, size = 63, normalized size = 1.07 \begin{align*} \frac{3 \,{\left (b x^{2} + a\right )}^{\frac{8}{3}}}{16 \, b^{3}} - \frac{3 \,{\left (b x^{2} + a\right )}^{\frac{5}{3}} a}{5 \, b^{3}} + \frac{3 \,{\left (b x^{2} + a\right )}^{\frac{2}{3}} a^{2}}{4 \, b^{3}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^5/(b*x^2+a)^(1/3),x, algorithm="maxima")

[Out]

3/16*(b*x^2 + a)^(8/3)/b^3 - 3/5*(b*x^2 + a)^(5/3)*a/b^3 + 3/4*(b*x^2 + a)^(2/3)*a^2/b^3

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Fricas [A]  time = 1.68285, size = 81, normalized size = 1.37 \begin{align*} \frac{3 \,{\left (5 \, b^{2} x^{4} - 6 \, a b x^{2} + 9 \, a^{2}\right )}{\left (b x^{2} + a\right )}^{\frac{2}{3}}}{80 \, b^{3}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^5/(b*x^2+a)^(1/3),x, algorithm="fricas")

[Out]

3/80*(5*b^2*x^4 - 6*a*b*x^2 + 9*a^2)*(b*x^2 + a)^(2/3)/b^3

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Sympy [B]  time = 1.57727, size = 631, normalized size = 10.69 \begin{align*} \frac{27 a^{\frac{32}{3}} \left (1 + \frac{b x^{2}}{a}\right )^{\frac{2}{3}}}{80 a^{8} b^{3} + 240 a^{7} b^{4} x^{2} + 240 a^{6} b^{5} x^{4} + 80 a^{5} b^{6} x^{6}} - \frac{27 a^{\frac{32}{3}}}{80 a^{8} b^{3} + 240 a^{7} b^{4} x^{2} + 240 a^{6} b^{5} x^{4} + 80 a^{5} b^{6} x^{6}} + \frac{63 a^{\frac{29}{3}} b x^{2} \left (1 + \frac{b x^{2}}{a}\right )^{\frac{2}{3}}}{80 a^{8} b^{3} + 240 a^{7} b^{4} x^{2} + 240 a^{6} b^{5} x^{4} + 80 a^{5} b^{6} x^{6}} - \frac{81 a^{\frac{29}{3}} b x^{2}}{80 a^{8} b^{3} + 240 a^{7} b^{4} x^{2} + 240 a^{6} b^{5} x^{4} + 80 a^{5} b^{6} x^{6}} + \frac{42 a^{\frac{26}{3}} b^{2} x^{4} \left (1 + \frac{b x^{2}}{a}\right )^{\frac{2}{3}}}{80 a^{8} b^{3} + 240 a^{7} b^{4} x^{2} + 240 a^{6} b^{5} x^{4} + 80 a^{5} b^{6} x^{6}} - \frac{81 a^{\frac{26}{3}} b^{2} x^{4}}{80 a^{8} b^{3} + 240 a^{7} b^{4} x^{2} + 240 a^{6} b^{5} x^{4} + 80 a^{5} b^{6} x^{6}} + \frac{18 a^{\frac{23}{3}} b^{3} x^{6} \left (1 + \frac{b x^{2}}{a}\right )^{\frac{2}{3}}}{80 a^{8} b^{3} + 240 a^{7} b^{4} x^{2} + 240 a^{6} b^{5} x^{4} + 80 a^{5} b^{6} x^{6}} - \frac{27 a^{\frac{23}{3}} b^{3} x^{6}}{80 a^{8} b^{3} + 240 a^{7} b^{4} x^{2} + 240 a^{6} b^{5} x^{4} + 80 a^{5} b^{6} x^{6}} + \frac{27 a^{\frac{20}{3}} b^{4} x^{8} \left (1 + \frac{b x^{2}}{a}\right )^{\frac{2}{3}}}{80 a^{8} b^{3} + 240 a^{7} b^{4} x^{2} + 240 a^{6} b^{5} x^{4} + 80 a^{5} b^{6} x^{6}} + \frac{15 a^{\frac{17}{3}} b^{5} x^{10} \left (1 + \frac{b x^{2}}{a}\right )^{\frac{2}{3}}}{80 a^{8} b^{3} + 240 a^{7} b^{4} x^{2} + 240 a^{6} b^{5} x^{4} + 80 a^{5} b^{6} x^{6}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**5/(b*x**2+a)**(1/3),x)

[Out]

27*a**(32/3)*(1 + b*x**2/a)**(2/3)/(80*a**8*b**3 + 240*a**7*b**4*x**2 + 240*a**6*b**5*x**4 + 80*a**5*b**6*x**6
) - 27*a**(32/3)/(80*a**8*b**3 + 240*a**7*b**4*x**2 + 240*a**6*b**5*x**4 + 80*a**5*b**6*x**6) + 63*a**(29/3)*b
*x**2*(1 + b*x**2/a)**(2/3)/(80*a**8*b**3 + 240*a**7*b**4*x**2 + 240*a**6*b**5*x**4 + 80*a**5*b**6*x**6) - 81*
a**(29/3)*b*x**2/(80*a**8*b**3 + 240*a**7*b**4*x**2 + 240*a**6*b**5*x**4 + 80*a**5*b**6*x**6) + 42*a**(26/3)*b
**2*x**4*(1 + b*x**2/a)**(2/3)/(80*a**8*b**3 + 240*a**7*b**4*x**2 + 240*a**6*b**5*x**4 + 80*a**5*b**6*x**6) -
81*a**(26/3)*b**2*x**4/(80*a**8*b**3 + 240*a**7*b**4*x**2 + 240*a**6*b**5*x**4 + 80*a**5*b**6*x**6) + 18*a**(2
3/3)*b**3*x**6*(1 + b*x**2/a)**(2/3)/(80*a**8*b**3 + 240*a**7*b**4*x**2 + 240*a**6*b**5*x**4 + 80*a**5*b**6*x*
*6) - 27*a**(23/3)*b**3*x**6/(80*a**8*b**3 + 240*a**7*b**4*x**2 + 240*a**6*b**5*x**4 + 80*a**5*b**6*x**6) + 27
*a**(20/3)*b**4*x**8*(1 + b*x**2/a)**(2/3)/(80*a**8*b**3 + 240*a**7*b**4*x**2 + 240*a**6*b**5*x**4 + 80*a**5*b
**6*x**6) + 15*a**(17/3)*b**5*x**10*(1 + b*x**2/a)**(2/3)/(80*a**8*b**3 + 240*a**7*b**4*x**2 + 240*a**6*b**5*x
**4 + 80*a**5*b**6*x**6)

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Giac [A]  time = 1.47091, size = 58, normalized size = 0.98 \begin{align*} \frac{3 \,{\left (5 \,{\left (b x^{2} + a\right )}^{\frac{8}{3}} - 16 \,{\left (b x^{2} + a\right )}^{\frac{5}{3}} a + 20 \,{\left (b x^{2} + a\right )}^{\frac{2}{3}} a^{2}\right )}}{80 \, b^{3}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^5/(b*x^2+a)^(1/3),x, algorithm="giac")

[Out]

3/80*(5*(b*x^2 + a)^(8/3) - 16*(b*x^2 + a)^(5/3)*a + 20*(b*x^2 + a)^(2/3)*a^2)/b^3